Riemannian Geometry Part 5

Question 01 / 37

Riemannian Geometry Part 5

Problem
Problem 6.140 Prove: 1. Every strictly conformal map is an immersion. 2. If $M$ is connected, then a strictly conformal map $$ f:(M, g) \rightarrow(\bar{M}, \bar{g}) $$ of ratio $\lambda$ transforms the Levi-Civita connection $\nabla$ of $g$ into the Levi-Civita connection $\bar{\nabla}$ of $\bar{g}$, if and only if $\lambda=$ const and the second fundamental form of the immersed submanifold $f(M)$ vanishes. 3. If $\lambda=1$, that is, $f$ is an isometry, and the second fundamental form of $f(M)$ vanishes, then if $R$ and $\bar{R}$ stand for the Riemann-Christoffel curvature tensors of $M$ and $\bar{M}$, respectively, one has $f_{*} R=\left.\bar{R}\right|_{f(M)}$.
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Source

PM. Gadea et al., Analysis and Algebra on Differentiable Manifolds,. Problem Books in Mathematics

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